1) arccos0-arccos√2/2- (arctg√3/3)/(arcctg√3)= Pi/2 -Pi/4-(Pi/6)/(Pi/6) = -1 + Pi/4

ответ: -1 +Pi/4

2) (6sina+5cosa)/(4sina-3cosa), если tga=3

[6sina/(4sina-3cosa) ]^-1 = (4sina-3cosa)/6sina = 4/6 -1/2tga = 4/6 - 1/6=1/2

[1/2]^-1 =2

[5cosa/(4sina-3cosa) ]^-1 = (4sina-3cosa)/5cosa = 4tga/5 -3/5 = 12/5 - 3/5=9/5

[9/5]^-1 =5/9

2+5/9=23/9

ответ 23/9